Generating infinite sequence of bytes set to ones
After trying to implement my own "one time pad (OTP)" file encryption. I ran into an issue that I needed large byte object sequence to write proper unit tests for encryption/decryption.
For those who don't know, python has a special
bytes object which stores "raw"
data so to speak. Example of
bytes in action:
>>> bytes(2) b'\x00\x00'
bytes output explained:
b'...' - indicates the the output is a byte string \x - escapes 'x' character with '\'. 'x' indicates that output in hex \x00 - 0 in hex. Also could be written as 00000000 in binary \x00\x00 - since we created 2 bytes we 2 bytes stored
To write a small function for generating N bytes that are always 0b1111.. e.g.
one_flood(1) -> b'\xff' # 0b11111111 255 in decimal one_flood(2) -> b'\xff\xff' # 0b11111111 11111111, 65535 in decimal one_flood(3) -> b'\xff\xff\xff' # 0b11111111 11111111 11111111, 16777215 in decimal ...
It should be noted that this code will only(reliably) work from python version >=3.7.
def one_flood(self, n_bytes: int): M = 0b11111111 # 255 a = 0 for _ in range(n_bytes): # on first iteration (a = 0) right shift (<<) does nothing. # only the OR operator (|) transforms a=0 -> a=255 a = (a << 8) | M return a.to_bytes(n_bytes, "big")
Why python >= 3.7?:
From this version and up
int object has the ability to
increase its size in bytes it variable if can't store any more data. On older
versions of python
int object would simply overflow. Now this does not happen
int can now be of any size.
why do we need
int objects if we are creating
unfortunately python does not support bitwise and logical operations on
object this means that we must use
int objects for that.